CBSE - MCQ Question Banks (के. मा. शि. बो . -प्रश्नमाला )

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Q. 189401 A laser beam is used for carrying out surgery, because it


A. is  highly monochromatic

B. is highly coherent

C. is highly directional

D. can be sharply focussed

Right Answer is: D

SOLUTION

A laser beam is highly monochromatic, directional  and coherent and hence it can be sharply focussed for carrying out surgery.


Q. 189402 In ‘radio’ mode of communication, there are a number of receivers for


A. one transmitter.

B. two transmitters.

C. three transmitters.

D. four transmitters.

Right Answer is: A

SOLUTION

In broadcast communication mode, there are several receivers corresponding to a single transmitter. Examples, Radio and T.V.


Q. 189403 An optical fibre has a core of refractive index 1.3. If the core cladding index difference factor (Δ) is 0.01225, then the numerical aperture is


A. 0.252

B. 0.225

C. 0.325

D. 0.203

Right Answer is: D

SOLUTION

NA = µ1(2d)1/2 = 1.3×(2×0.01225)1/2 =0.203


Q. 189404 Before giving a voice signal as an input to a transmitter, it should be processed by using a


A. transducer.

B. transformer.

C. diode.

D. transistor.

Right Answer is: A

SOLUTION

If the output of the information source is a voice signal, to use it as input for transmitter, it should be converted into electrical energy by using a transducer (a device which can convert energy from one form to another).


Q. 189405 The process of superimposing an audio signal to high frequency carrier wave is called


A. transmission.

B. communication.

C. modulation.

D. demodulation.

Right Answer is: C

SOLUTION

The original low frequency message signal cannot be transmitted to long distances. Therefore, at the transmitter, low frequency message signal is superimposed on a high frequency wave. This process is known as modulation.


Q. 189406 If a TV tower is of H height, then the maximum distance upto which the TV transmission received is proportional to


A. H3/2

B. H

C. H1/2

D. H2

Right Answer is: C

SOLUTION


Q. 189407 The ozone layer absorbs


A. infrared radiations.

B. ultraviolet radiations.

C. X-rays.

D. visible light.

Right Answer is: B

SOLUTION

Ozone layer absorbs high energy radiations like ultraviolet rays falling on it, while it transmits visible light and reflects infrared radiations.


Q. 189408 Modulation facilitates the transmission of


A. high frequencies over long distances.

B. high frequencies over short distances.

C. low frequencies over long distances.

D. low frequencies over short distances.

Right Answer is: C

SOLUTION

Low frequency signals cannot be transmitted over long distances. Modulation is the superimposition of low frequency signal on a high frequency carrier signal. Thus, modulation facilitates the transmission of low frequency signals over long distances.


Q. 189409  


A. 10 %.

B. 20 %.

C. 40 %.

D. 50 %.

Right Answer is: D

SOLUTION


Q. 189410 The length of dipole antenna for carrier wave of frequency 1 GHz is


A. 0.60 m.

B. 0.30 m.

C. 0.15 m.

D. 0.10 m.

Right Answer is: C

SOLUTION


Q. 189411 A band width of 20 MHz is available for amplitude modulated transmission. If the audio signal modulating is less than 20 kHz, the number of stations that can be broadcasted within this band without any interference is


A. 20.

B. 50.

C. 100.

D. 500.

Right Answer is: D

SOLUTION


Q. 189412 A T.V. tower has a height of 100 m. It covers a total population of 50 lakhs. The average population density around the T.V. tower is


A. 1244 km-2.

B. 2444 km-2.

C. 1422 km-2.

D. 4211 km-2.

Right Answer is: A

SOLUTION


Q. 189413 An audio signal is sampled every 125 microseconds using 16 quantisation levels. The bit rate for the signal is


A. 8000 bits per second.

B. 32000 bits per second.

C. 128,000 bits per second.

D. 328,000 bits per second.

Right Answer is: B

SOLUTION


Q. 189414 Why is short wave band used for long distance radio broadcast?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

Short waves have the frequency range of 2MHz to 20MHz. These waves can be reflected to earth by a layer of atmosphere called ionosphere. Hence we can use these waves for long distance radio transmission.


Q. 189415 Find the length of the dipole antenna for a carrier wave of wavelength ?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The length of the dipole antenna will be equal to / 2.


Q. 189416 What do you mean by bandwidth?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The total spread of a signal over a range of frequencies is called its bandwidth.


Q. 189417 How does the power radiated by an antenna vary with wavelength?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The power radiated by an antenna is related to wavelength by relation,

  ( 1 / 2).


Q. 189418 Name the type of modulation scheme preferred for digital communication.
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

For digital communication we prefer pulse code modulation (P.C.M).


Q. 189419 What is sampling frequency?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The number of samples taken per second for a given analog signal is called its sampling frequency.


Q. 189420 How would the following be affected in the absence of atmosphere around the earth?   
a)    Surface temperature of earth.
b)    Range of radio waves transmission.
Give brief explanation in support of your answer.
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

a) The temperature of earth will decrease since the greenhouse effect will not take place in absence of atmosphere.
b) Range of radiowaves will decrease since reflecting layer(ionosphere) will be absent.

 


Q. 189421 A T.V tower has a height of 80m.What is its coverage area?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The coverage area is given by,

 d= ( 2hR )1/2, where h=Height of the tower and R=radius of earth.

d= ( 2 x 80 x 6.4 x 106 )1/2 = 22627.5 m = 22.62 km.

  


Q. 189422 What is geostationary satellite ? What are its two characteristics?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

Geostationary satellite: The satellite which appears to be at a fixed position to an observer on earth is called geostationary satellite.

The two characterstics of geostationary satellite are given as follows:

  1. It remains at a height of about 36,0000 km above the equator of earth.
  2. Its period of revolution should be equal to rotation of earth about its own axis i.e. 24 hours.  


 


Q. 189423 Give two advantages of optical fibre communication?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The two advantages of optical fibre communication are given as follows:-
1. It can carry large amount of information signals at once.
2. It is able to carry even the high bandwidth carrier signals.

 


Q. 189424 What are the four primary constants of a transmission line?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The four primary constants of a transmission line are given as follows:-

  1. Resistance(R).
  2. Inductance(L).
  3. Capacitance(C).
  4. Conductance(G).

 


Q. 189425 What should be the length of a dipole antenna for a carrier wave having frequency 3x108 Hz?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

Length of dipole antenna = / 2-----I.

We are given with the frequency of carrier wave, evaluate wavelength from it by relation,

= c / f = ( 3 x 108 ) / ( 6 x 108 ) = 0.5 m.

Substituting the above value in equation I we get,

Lemgth of dipole antenna=(0.5 / 2) = 0.25 m.


Q. 189426 Explain how communication is possible with the help of sky wave propagation?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

 In this type of communication the radiowaves transmitted and directed towards the sky are reflected back to earth at a distant location by the help of layer of atmosphere, also called as ionosphere.
The signal transmitted in this case must belong to the frequency range between 1710 kHz to 54 MHz. These waves are also called as short waves and are used for the transmission of radio signals. Ionosphere is the uppermost layer of the earth’s atmosphere and is located at the altitude of 65 km to 400 km. It contains ionized layers of electrons and ions, which are responsible for reflecting the transmitted signal back to earth. The signals which are above 54 Mhz escapes ionosphere and are not reflected back. Hence we can say that only a range of frequencies can be transmitted back towards earth. 


Q. 189427 What are the processes involved in converting analog signal into digital signal? Explain pulse amplitude modulation (P.
A.M).
Right Answer is:

SOLUTION

The steps involved in converting analog signal into digital signal is shown below with the help of block schematic below,




Pulse Amplitude Modulation: In pulse amplitude modulation the pulses of the carrier pulse train is varied in accordance with the instantaneous value of the modulating signal.
Here from the figure below we can say that in pulse amplitude modulation the amplitude of pulses increseases or decreases in accordance with the modulating signal. In case of the pulse amplitude modulation the modulating signal is mixed with the modulating information signal to get the train of pulse amplitude signals. The pulse amplitude signal may be of single polarity or double polarity. If the train of pulses exists only in one direction than it is double polarity type P.A.M and if the pulses are present in both direction then it is called as double polarity P.A.M.


Q. 189428 What is satellite communication ? Explain its working.
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

 The communication of signal between transmitter and receiver with the help of satellite is called as satellite communication.
Working: A satellite receives the signals from earth (which is beamed by transmitter), processes the signals and transmits them back to earth. The signal beamed by the satellite is received back on a distant location on earth, from which the original information signal is extracted by the process called demodulation.
The frequency at which satellite receive the signal is called as uplink frequency while the frequency at which satellite returns the signal towards earth is called as downlink frequency. The downlink frequency and uplink frequency are different so that there is no interference between these two signals.

 


Q. 189429 What are the merits and demerits of satellite communication?
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The merits of satellite communication are given as follows:
1. It has a wide coverage area as compared to other communication systems.
2. Transmission of data at very high rate is possible through satellite communication.
3. Communication can be done from any part of earth just by using three geostationary satellites.
4. Communication done by the help of a satellite is much cheaper than other available means.
Demerits of satellite communication are given as follows:
1. The cost of launching satellite is very high and needs lot of technology expertise.
2. Every satellite has got its own time frame of working, after which it expires.
3. If there anything goes wrong in the satellite then there is no way we can fix the problem.
4. There is time delay between transmission and reception of signals, since they have to travel long distance(2x36,000=72,000 km).

 


Q. 189430 What do you mean by remote sensing? Give its applications.
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

Remote Sensing: Remote sensing is a technique by which we can obtain information about a particular geographical area or object, from a distance without being in physical contact.
Applications of remote sensing: The applications of remote sensing are given as follows:-
1. By the help of remote sensing we can find out the information of cultivation of different crops in a particular area.
2. It is used in study and making of different kinds of maps also knowm as cartography.
3. It is used in oceanography i.e. for knowing the climatic condition, temperature and also to identify the potential fishing zones.
4. Remote sensing is useful in finding out the extent of pollution in any particular region and its sources too.
5. Remote sensing is used in predicting the temperature and weather and other climatic condition of a given area in advance.
6. It is also used during the period of natural calamities to assess the damage caused.
7. Remote sensing is used for spying in the field of defence and during war to locate the enemies.
8. It is used in the field of forestry. Remote sensing can give information about extent of forest cover, density of forest and types of plants. It is also helpful in detection and prevention of forest hazards like fire, excessive falling of of trees, etc.

 

 


Q. 189431 What is amplitude modulation? What is modulation index? Derive the expression for modulation index.
A. 8000 bits per second.
B. 32000 bits per second.
C. 128,000 bits per second.
D. 328,000 bits per second.

Right Answer is:

SOLUTION

The variation of the amplitude of a carrier wave in accordance with the instantaneous value of the modulating(information) signal is called as amplitude modulation. The concept of generation of amplitude modulated signal is shown in the figure below,

 

  

Here the instantaneous value of the modulating signal is given by equation,

 em=Emsinm t------(I) ;where, m is the angular frequency of the modulating signal.

Similarly the instantaneous value of the carrier signal is given by,

 ec=Ecsinct--------(II) ;where, c is the angular frequency of the carrier signal.

Modulation Index: The ratio of amplitude of modulating signal to the amplitude of carrier is called as modulation index. It is also called as degree of modulation or depth of modulation. It is denoted by ma.

 Here we have to find the expression for the ratio Em/Ec.

From fig(b), it follows that:-

 Em= (Emax - Emin)/2     ----------(III)

Similarly,

Ec= Emax - E

Subsituting the value of Em from equation (III), we get:-

 Ec= Emax -  (Emax - Emin)/2

 Ec= (Emax - Emin)/2    ------------(IV)

Dividing equation (III) by (IV),

ma = Em/Ec = (Emax - Emin)/(Emax + Emin)


Q. 189432 A structure is declared with the keyword


A. structure.

B. struct.

C. define.

D. tag.

Right Answer is: B

SOLUTION

A structure is declared using keyword struct. 

For example : 

struct student
{
   int class;
   int rollno;
   float marks;
   char grade;
};


Q. 189433 The error in the code below is # include < iostream.h >
const int i =10;
void main()
{
const int i =20;
cout < < &i < < &::i ;
}


A. compiler error : illegal structure declaration.

B. no error.

C. :: cannot be used with constant.

D. run time error.

Right Answer is: A

SOLUTION

&::i is a illegal declaration used in the code.


Q. 189434 The errors in the code below is -

#include < iostream.h >
void main()
{
char c[]=”C++ is easy”;
int i = strlen (c) ;
cout < < i ;
}


A. no error.

B. c cannot be passed as an argument. It should be c[].

C. string .h header file is not defined.

D. no return statement for main ().

Right Answer is: C

SOLUTION

“ string.h ” header file defines string functions in it like strlen, strcpy etc. These functions cannot be used without using string.h header file.  


Q. 189435 The errors in the code below is -

#include < iostream.h >
int a=10;
void main()
{
int a=20;
{
int a=30;
cout < <   a  < < ::a < < ::::a ;
}
}


A. compiler error.

B. no error.

C. :: and :::: cannot come together.

D. no return statement for main ().

Right Answer is: A

SOLUTION

“ :::: ” does not exist in C++ and it will give illegal structure declaration.


Q. 189436 The correct output of the following program is
#include < iostream.h >
void main()
{
for( int i=1; i<=10; i++ )
cout < < i < < endl ;
cout < < i ;
}


A. 1 2 3 4 5 6 7 8 9 10 1.

B. 1 2 3 4 5 6 7 8 9 10 10.

C. 1 10.

D. 1 2 3 4 5 6 7 8 9 10.

Right Answer is: B

SOLUTION

The for loop prints values of i from 1 to 10. 10 will be printed twice.


Q. 189437 The correct output of the following program is
#include < iostream.h >
void main()
{
int i ; 
cout < < sizeof (i)  < < endl < < sizeof (‘i’);
}


A. 2 1.

B. 2 2.

C. 1 1.

D. 1 2.

Right Answer is: A

SOLUTION

Integer takes 2 bytes of memory and char takes 1 byte of memory in C++.  A variable within a single code represent a character.


Q. 189438 The correct output of the following program is
#include < iostream.h >
int i=25;
void main()
{
int i=5;
cout < < i  < < endl < < ::i ;
{
int i=10;
cout < < i  < < endl < < ::i ;
}
}


A. 5 5 25 25

B. 5 25  10 5.

C. 5 25 5 25.

D. 5 25 10 25.

Right Answer is: D

SOLUTION

:: is a scope resolution operator, which is used to access global value of i.


Q. 189439 The correct output of the following program is -

#include < iostream.h>
void main()
{
char *p=”abc”;
char *q=p;
cout < < p < < endl < < q ;
q=”xyz”;
cout < < p < < endl < < q ;
}


A. abc xyz abc xyz.

B. abc abc abc xyz.

C. abc abc xyz xyz.

D. abc abc abc abc. 

Right Answer is: B

SOLUTION

The value of p is assigned to pointer q . So initially *p and * q will point to the same string, i.e., abc.


Q. 189440 The correct output of the following program is
#include < iostream.h >
void main()
{
int i=5;
int &j=i;
int p=10;
j=p;
cout< < endl < < i < < endl < < j;
p=20;
cout < < endl < < i  < < endl < < j;
}


A. 10 10 10 10.

B. 10 5 20 20.

C. 5 10 10 10.

D. 10 10 20 20.

Right Answer is: A

SOLUTION

Here, j is a reference to i. If we assign value of p to j, then i will also start pointing to the value of p, i.e., 10.


Q. 189441 Error in the code below is
main()
{
int i, j;
int *ip;
i=j=ip=0;
}


A. pointer cannot be used in assignment statement.

B. ip is a pointer and cannot be used as integer.

C. pointer should not be initialized.

D. pointer can not be equal to zero.

Right Answer is: B

SOLUTION

A pointer points to the address of a variable. It cannot be used as integers.


Q. 189442 Error in the code below is
main()
{
int i=j=k=0;
}


A. multiple assignment statement requires pre declaration of variables.

B. multiple assignment is not possible.

C. initialization should be outside the braces.

D. every variable should be declared independently.

Right Answer is: A

SOLUTION

Here, j and k are not being declared before using assignment operation. The correct way is int i, j ,k; to be used before assignment.


Q. 189443 Assuming that res starts with the value 25, the result of the following code fragment is cout < < res--;
cout > > ++res;


A. 25 25

B. 25 24

C. 24 25

D. 24 26

Right Answer is: A

SOLUTION

res-- is a post decrement operator. First it will print the value and then the value will be decreased by 1. ++res is a pre increment operator, it will first increment the value and then print the result.


Q. 189444 The statement which is valid or legal in C++ is


A. A reference can be used without proper initialization.

B. Array of references is legal in C++.

C. char, int pointers can refer to null pointers but null pointers cannot refer to other pointers.

D. Array of pointers is not legal in C++.

Right Answer is: C

SOLUTION

A reference has to be properly initialized, otherwise it will result in an error. In C++, special care is taken for assignment of void pointers to other pointer types. While we can assign a pointer of any type to a void pointer, the reverse is not true until we do explicit typecasting.


Q. 189445 The ability to reuse objects already defined, perhaps for a different purpose, with modification appropriate to the new purpose, is referred to as


A. information hiding.

B. inheritance.

C. redefinition.

D. overloading.

Right Answer is: D

SOLUTION

A type of polymorphism where different functions with the same name are invoked based on the data types of the parameters passed is called overloading.


Q. 189446 The correct statement according to the code below is - void *a;
char *b;
a=b;
b=a;


A. this is correct.

B. it would give an error as ‘a’ cannot be assigned to ‘b’.

C. it would give an error as ‘b’ cannot be assigned to ‘a’.

D. error in statement 3 and 4.

Right Answer is: B

SOLUTION

In C++, void pointer cannot be assigned to the pointer of any type. This would result in an error of type mismatch. It can be made true when we explicitly typecast it, b=(char*) a;


Q. 189447 The correct statement according to the code below is
          struct aditi {
                     union {
                                  int i;
                                 char ch[2];
                                } ;   
                              };


A. this would give an error as no union name defined.

B. nesting union within struct is not allowed.

C. this is correct and legal in C++.

D. this is correct and legal in C and C++.

Right Answer is: C

SOLUTION

This is legal in C++ but not in C. Unions, which do not have a class name, are anonymous union.


Q. 189448 When structure is defined without a tag, then the number of variables that can be declared are/is


A. two.

B. three.

C. many.

D. only one.

Right Answer is: D

SOLUTION

One variable is declared when structure is defined without a tag.


Q. 189449 The function to handle multiple characters from the keyboard is


A. gets( ).

B. getline( ).

C. get( ).

D. put( ).

Right Answer is: A

SOLUTION

The function gets() is a string function that reads a string i.e. multiple characters from the keyboard including white spaces etc.


Q. 189450 The function to handle single character from the keyboard is


A. gets( ).

B. getline( ).

C. get( ).

D. put( ).

Right Answer is: C

SOLUTION

The get() function is an input function. It fetches the character from the keyboard and stores it in a character variable.


Q. 189451 The function getline is invoked with


A. cin stream.

B. cout stream.

C. ostream.

D. input stream.

Right Answer is: A

SOLUTION

The function getline() is invoked using cin. Example cin.getline(string1,50). String1 is the name of the array and 50 is the number of characters, we want this function to read.


Q. 189452 The header file, which define types and macros needed for the standard I/O package, is


A. conio.h

B. iostream.h

C. stdio.h

D. string.h

Right Answer is: C

SOLUTION

The stdio.h is a standard input output header file. These have libraries of code which we may insert in the program, by using as a reference in the top block.


Q. 189453 seekg() function belongs to


A. stream class.

B. xstream class.

C. zstream class.

D. fstream class.

Right Answer is: D

SOLUTION

fstream is an input-ouptput functions of stream class. It provides support for simultaneous input and output operations.


Q. 189454 The header file which declares various functions used in calling Dos Console I/O routines, is


A. conio.h

B. iostream.h

C. stdio.h

D. string.h

Right Answer is: A

SOLUTION

The term conio.h is a console input output header file. These have libraries of code which we may insert in the program, by using as a reference in the top block.


Q. 189455 The correct statement is


A. function getline() can read white spaces ( spaces, tabs etc.).

B. function getline() and gets() are same functions.

C. getline(), putline(), get() and put() functions are defined in stdio.h.

D. gets() and puts() are defined in iostream.h.

Right Answer is: A

SOLUTION

getline(), putline(), get() and put() functions are unformatted stream of functions in header file, i.e., iostream.h, whereas gets() and puts() are string functions in stdio.h.


Q. 189456 The output of the code: a+=a++ + ++a, when a=20 initially, is


A. 64.

B. 61.

C. 42.

D. 41.

Right Answer is: A

SOLUTION

The post-increment operator first prints the value and then increments, whereas the pre-increment operator first increments the value then print.


Q. 189457 The result of following expression, ans-( val < 500?150:50) when ans=800 val=700, is


A. 700.

B. 750.

C. 150.

D. 650.

Right Answer is: B

SOLUTION

According to the precedence of operators, bracket will be evaluated first.


Q. 189458 The run-time error is possible when


A. file could not be opened.

B. MAX+2=DMAX

C. missing of semicolon at the end of code.

D. statements are wrongly written violating rules of a program.

Right Answer is: A

SOLUTION

Run time error is an error that occurs during the execution of a program. The compilation is not affected by it.


Q. 189459 The invalid real constant is


A. 2.0.

B. 17.5.

C. 72,340.42.

D. -0.00987.

Right Answer is: C

SOLUTION

Real constants are numbers having fractional parts. These may be written in fractional form or exponent form. It must have at least one digit before decimal and one digit after decimal and commas are not allowed.


Q. 189460 The identifier which is NOT legal is


A. Myfile

B. _chk

C. break

D. _hj_as

Right Answer is: C

SOLUTION

Keywords are not acceptable as identifier in C++. break is a keyword.


Q. 189461 An if statement tests


A. particular conditions.

B. single conditions.

C. set of instructions.

D. instructions to be performed repeatedly.

Right Answer is: A

SOLUTION

if statement tests a particular condition; if the condition evaluates to true then action is performed otherwise action is ignored.


Q. 189462 sizeof() operator used in C++ programs accepts


A. one parameter only.

B. two parameters only.

C. one or more parameters.

D. multiple parameters.

Right Answer is: A

SOLUTION

sizeof() operator accepts one parameter which can either be a type or a variable itself and return the size in bytes of that type or object.


Q. 189463 The main advantage of OOPs is


A. reusabilty of code.

B. time consuming.

C. complex coding.

D. high maintenance requirement.

Right Answer is: A

SOLUTION

OOPs programs are built from reusable software components. It saves time and is easier to work with.


Q. 189464 ‘ n ’ which is used in c++ is an


A. escape sequence for start.

B. escape sequence for end.

C. escape sequence for null.

D. escape sequence for new line.

Right Answer is: D

SOLUTION

'n' sends the new line character but does not flush the output buffer.


Q. 189465 A class in C++ is known as empty class if it


A. has more than a name.

B. has no member functions.

C. is just a name.

D. has no common properties.

Right Answer is: C

SOLUTION

An empty class has no variable declarations, no functions or methods but objects of these classes can have a non–zero size.


Q. 189466 The error in this statement  "cout " << "computers can be fun" ;


A. > > should be used instead of < <.

B. cout enclosed within double quotes.

C. there should be a space between < and <.

D. semicolon should not be used.

Right Answer is: B

SOLUTION

Correct sentence is cout < < " computers can be fun ” ;


Q. 189467 The header file in which clrscr() function is present is


A. conio.h.

B. stdio.h.

C. iostream.h.

D. iomanip.h.

Right Answer is: A

SOLUTION

clrscr() is a console input output function which is defined in conio.h header file.


Q. 189468 Interface is also known as


A. virtual class.

B. dependent class.

C. pure abstract class.

D. class.

Right Answer is: C

SOLUTION

Interface generally refers to an abstraction that an entity provides of itself to the outside. This separates the methods of external communication from internal operation and allows it to be internally modified without affecting the way outside entities interact with it, as well as provide multiple abstractions of itself.


Q. 189469 A variable used in C++ can be tied with


A. zero reference.

B. only one reference.

C. two references.

D. several references.

Right Answer is: D

SOLUTION

We can create two or more references for the same variable but same reference can not be tied with several variables.


Q. 189470 When a class uses dynamic memory, the member function invoked by the class is


A. an overloaded assignment operator.

B. a destructor.

C. a copy constructor.

D. no member functions provided.

Right Answer is: B

SOLUTION

In dynamic memory allocation, whenever the object is out of scope, its memory would be freed and deallocated. So, a destructor is automatically invoked by the class.


Q. 189471 An abstract class is the class that


A. does not have method definitions.

B. has a constructor which takes no arguments.

C. must have a function definition equal to zero.

D. can only exist during the planning phase.

Right Answer is: A

SOLUTION

Abstract classes are classes, which cannot be instantiated but they can have sub classes. They do not have method definitions but the prototypes and declarations can be done.


Q. 189472 An example of a method that is shared by all instances of a class is


A. a constructor.

B. an attribute.

C. a constructor and an attribute.

D. an overloading.

Right Answer is: A

SOLUTION

A constructor is a special member function, which will construct an object with user-defined values, whenever an object is created. It is a special method used in OOP, which puts the object member into a valid state.


Q. 189473 The other name for inheritance graph is


A. visibilty graph.

B. derivation graph.

C. derived graph.

D. hierarchy graph.

Right Answer is: B

SOLUTION

Inheritance graph (also known as derivation graph) is the chain depicting the derivation of a class from multiple base classes.


Q. 189474 A frequency modulated wave is represented by an equation, e = 10 sin (5  108t + 6 sin1000t). The carrier frequency is


A. 79.62 MHz.

B. 79.26 MHz.

C. 31.26 MHz.

D. 79.31 MHz.

Right Answer is: A

SOLUTION


Q. 189475 An audio signal of 2000 Hz modulates a carrier generated by a tank circuit comprising of a capacitor of 10-10 F and a coil of 10-5 H. The frequency of side bands is


A. 1602 kHz and 1582 kHz.

B. 2602 kHz and 2582 kHz.

C. 4045 kHz and 4025 kHz.

D. 5045 kHz and 5025 kHz.

Right Answer is: D

SOLUTION


Q. 189476 The wave which is unable to transmit intelligence to far off places is


A. sound wave.

B. T.V. wave.

C. microwave.

D. radio wave.

Right Answer is: A

SOLUTION

The velocity of electromagnetic waves (T.V. wave, microwave, radio wave etc.) is 3  108 ms-1. On the other hand, the velocity of sound waves is 332 ms-1. Therefore, sound wave is unable to transmit intelligence to far off places.


Q. 189477 The band width of amplitude modulation transmission if the carrier frequency and the modulating frequency are 150 KHz and 4 KHz, respectively, is


A.  8 kHz.

B. 146 kHz.

C. 154 kHz.

D. 300 kHz.

Right Answer is: A

SOLUTION


Q. 189478 The device of a communication system that reconstructs a recognisable form of the original message signal for delivering it to the user of information is the


A. transmitter.

B. channel.

C. receiver.

D. antenna.

Right Answer is: C

SOLUTION

Along the channel, a transmitted signal may get distorted due to channel imperfection and noise may add to it. The receiver, therefore, gets a corrupted version of the transmitted signal. The receiver operates on the received signal before delivering the signal to the user of the information.


Q. 189479 A carrier wave has amplitude of 0.50 V. The modulating signal causes it to vary from 0.20 V to 0.80 V. The amplitude of the modulating wave is


A. 0.5 V.

B. 0.3 V.

C. 0.2 V.

D. 0.1 V.

Right Answer is: B

SOLUTION


Q. 189480 A 1000 kHz carrier is modulated with 600 Hz of audio signals. The frequencies of first pair of side bands are


A. 1000.6 kHz and 999.4 kHz

B. 1000 kHz and 600 Hz

C. 1000.6 kHz and 600 Hz

D. 600 Hz and 999.4 kHz

Right Answer is: A

SOLUTION

fSB = fc ±fm = 1000 ± 0.6       = 1000.6 kHz and 999.4 kHz


Q. 189481 The length of a half wave dipole at 30 MHz is


A. 10 m.

B. 50 m.

C. 5 m.

D. 100 m.

Right Answer is: C

SOLUTION


Q. 189482 A laser beam of power 1014 watt is focused on an object that has an area of 10-3 cm2. What is the energy flux at the point of focus?


A. 1017 W/m2

B. 1021 W/cm2

C. 1017 W/cm2

D. 1018 W/m2

Right Answer is: C

SOLUTION

Energy flux = Power / area = 1017 W/cm2


Q. 189483 A transmitting antenna at the top of a tower has a height 32 m and the height of the receiving antenna is 50 m. What is the maximum distance between them for satisfactory communication in LOS mode? (Given radius of earth 6.4x106 m)


A.   35.5 km. 

B.  42.5 km.

C.  45.5 km.

D.  10.45 km.

Right Answer is: C

SOLUTION

   


Q. 189484 The radio waves of frequency 300 MHz to 3000 MHz belongs to


A. High frequency band

B. Very high frequency band

C. Ultra high frequency band

D. Super high frequency band

Right Answer is: C

SOLUTION

The radio waves of frequency 300 MHz to 3000 MHz belongs to Ultra high frequency band.


Q. 189485 Optical fibers are the best medium of transmission over copper wires because


A.   The loss of data in optical fibres is large

B.  It is cheap

C.  Easy to construct

D.  The optical fibre can take large number of telephonic message at a time

Right Answer is: D

SOLUTION

Optical fibre is always preferred over copper wires for transmission as fibres is very less and it can take large number of telephonic message at a time.


Q. 189486 For the transmission of audio signals ,


A. high frequncy carrier wave is used.

B. intermediate frequncy carrier wave is used.

C. low frequncy carrier wave is used.

D. no  frequncy carrier wave is required.

Right Answer is: A

SOLUTION

For the transmission of audio signals ,high frequncy carrier wave is used as they can ttravel through the space or medium with th espeed of light and they are not obstructed by earth`s atmospere.


Q. 189487 For ionospheric transmissions, it is desirable to use


A. frequency as high as possible.

B. frequency as low as possible.

C. frequency of intermediate range.

D. very low frequency.

Right Answer is: A

SOLUTION

The loss of kinetic energy of the wave while passing through the lower ionosphere layer is inversely proportional to the square of the frequency.


Q. 189488 With altitude, the electrical conductivity of the earth’s atmosphere


A.  Does not change

B.  Decreases

C.  Increase 

D.  Does not depend on altitude

Right Answer is: B

SOLUTION

The electrical conductivity of earth’s atmosphere increases with altitude because the high energy particles coming from outer space while entering earth’s atmosphere cause ionization of the atoms of the gases present in the atmosphere and their energy decreases as they approach to earth.


Q. 189489 The process of separating radio signal from the modulated wave is known as:


A. superimposition

B. amplification

C. demodulation

D. modulation

Right Answer is: C

SOLUTION

In the process of demodulation, carrier wave and modulating waves get separated.


Q. 189490 Modulated carrier wave contains the frequencies


A. c, c + m.   

B. c  m.  

C. c - m.

D. cc  m.

Right Answer is: D

SOLUTION

c - m and c + m are respectively called the lower side and upper side frequencies. The modulated signal now consists of the carrier wave of frequency c plus ten sinusoidal waves each of frequency slightly different from, known as side bands


Q. 189491 Preceding the detection, the carrier frequency is usually changed to


A. Higher frequency

B. Intermediate frequency

C. Lower frequency

D. Does not change at all.

Right Answer is: C

SOLUTION

The transmitted message gets attenuated in propagating through the channel. The receiving antenna is therefore to be followed by on amplifier and a detector. In addition, to facilitate further processing, the carrier frequency is usually changed to a lower frequency because the detected signal may not be strong enough to be made use of and hence is required to be amplified.


Q. 189492 Broadcast frequencies (carrier waves) are sufficiently spaced out so that


A.   Sidebands are clear 

B.  Sidebands do not overlap

C.  Only one side band will produce

D.  Two side bands only

Right Answer is: B

SOLUTION

As long as the broadcast frequencies are sufficiently spaced out so that sidebands do not overlap, different stations can operate without interfering with each other.


Q. 189493 In amplitude modulation


A.   1.

B.   1.

C.  = 1.

D.  = 0.

Right Answer is: A

SOLUTION

In case of amplitude modulation  = Am/Ac is kept  1 to avoid distortion.


Q. 189494 Suppose the amplitude of the modulating wave equals the signal amplitude. Then, the modulation index is 


A. 0.

B. 1.

C. 2.

D. 3.

Right Answer is: B

SOLUTION


Q. 189495 Interference, an undesirable effect in signal transmission, occurs most often in


A. radio wave transmission.

B. microwave transmission.

C. infrared transmission.

D. T.V. wave transmission.

Right Answer is: A

SOLUTION

Interference, an undesirable effect in signal transmission, occurs most often in radio transmission whose receiving antennas usually intercept several signals at the same time.


Q. 189496 The undesirable effect in course of the signal transmission which disappears when the signal is turned off is


A. attenuation.

B. distortion.

C. interference.

D. noise.

Right Answer is: B

SOLUTION

Distortion is waveform perturbation caused by imperfect response of the communication system to the desired signal itself. Therefore, it disappears when the signal is turned off.


Q. 189497 Frequency which will be suitable for beyond the horizon communication using sky waves is


A. 10 kHz.

B. 10 MHz.

C. 1 GHz.

D. 1000 GHz.

Right Answer is: B

SOLUTION

Sky wave propagation is suitable in the frequency range from a few MHz to 40 MHz. 10 kHz cannot be radiated due to impracticable antenna size while 1 GHz and 1000 GHz will penetrate the atmosphere.


Q. 189498  The degree of ionisation of atmosphere is


A. highest at great heights.

B. highest at low heights.

C. highest at the intermediate heights.

D. constant at all heights.

Right Answer is: C

SOLUTION

The degree of ionisation of atmosphere varies with height due to the variation in solar radiation and molecular concentration. The density of atmosphere decreases with height. Although the solar radiation is intense at higher altitude, there are few molecules to be ionised. Near the earth’s surface, the molecular concentration is high but the solar radiation is low; hence, low ionisation results. The degree of ionisation is therefore highest at the intermediate heights.


Q. 189499 The coverage range of a T.V. tower is 31 km. The coverage area of the same T.V. tower is


A. 97.34 km2.

B. 1509 km2.

C. 3018 km2.

D. 6036 km2.

Right Answer is: C

SOLUTION


Q. 189500 A T.V. transmission tower at a particular station has a height of 160 m. The coverage range is


A. 45.26 km.

B. 50.23 km.

C. 80 km.

D. 81.3 km.

Right Answer is: A

SOLUTION


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